# The members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball and $30.00 per football, spending a total of $648.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?

**Answer:**

Number of basketball = 9

Number of football = 15

**Step-by-step explanation:**

let number of basketball = x

let number of football = y

Given that cost of 1 basketball = 22

Then cost of x basketball = 22x

Given that cost of 1 football = 30

Then cost of x football = 30y

Then total expense = 22x+30y

Given total expense is $648 so we can set both equal to each other and get:

22x+30y=648...(i)

Given that they bought 6 more footballs than basketballs

so we get:

y=6+x...(ii)

Now plug (ii) into (i)

22x+30y=648

22x+30(6+x)=648

22x+180+30x=648

52x+180=648

52x=648-180

52x=468

x=9

plug x=9 into (ii)

y=6+x=6+9=15

Hence final answer is :

Number of basketball = 9

Number of football = 15

If your question is not fully disclosed, then try using the search on the site and find other answers on the subject Mathematics.

Find another answersMathematics, published 11.05.2023

Mathematics, published 23.03.2023

Use the equation to identify the center and radius of the circle (X+3)^2+(y-7^2=11

Mathematics, published 27.05.2023