A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7N. What is the acceleration of the box?

Answer by Guest

Answer:

1.76 m/s^2

Explanation:

mass of box, m = 5.5kg

net force , F = 9.7N

acceleration = ?

F = m x a

a = F/m = 9.7/5.5

a = 1.76 m/s^2

If your question is not fully disclosed, then try using the search on the site and find other answers on the subject Physics.